Reversing

In this program, we have to find reverse of a no. For eg:- if number is 27654 then reverse number will be 45672 . 

Formula used : - 

                       eg:- no. is 456

456 = 6 + 5*10 + 4*100.        this  logic is used.

line a = n%10; is used to seperate single digits i.e if no. is 456 then after this line a=6

line n = n/10 is use to decrease the total no. ie if no. is 456 after this line it would be 45 only in n.

So, in this way we reverse a number..

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Program to reverse a number.

#include<stdio.h>

#include<conio.h>

void main()

{       int n,rev=0,a;

clrscr();

printf("program to reverse a number :");

printf("\n\n enter no. to reverse :");

scanf("%d",&n);

while(n!=0)

{    a = n%10;

    rev  = rev*10 + a;

    n = n/10;

}

printf("\n\n no. after reverse = %d",rev);

getch();

}